Whakaoti i te (2a+1)^3-2a(2a+1)^2-(2a)^2-1

$$( 2 a + 1 ) ^ { 3 } - 2 a ( 2 a + 1 ) ^ { 2 } - ( 2 a ) ^ { 2 } - 1$$

Aromātai

$$4a$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(p+q\right)^{3}=p^{3}+3p^{2}q+3pq^{2}+q^{3} hei whakaroha \left(2a+1\right)^{3}.

$$8a^{3}+12a^{2}+6a+1-2a\left(2a+1\right)^{2}-\left(2a\right)^{2}-1$$

Whakamahia te ture huarua \left(p+q\right)^{2}=p^{2}+2pq+q^{2} hei whakaroha \left(2a+1\right)^{2}.

$$8a^{3}+12a^{2}+6a+1-2a\left(4a^{2}+4a+1\right)-\left(2a\right)^{2}-1$$

Whakarohaina te \left(2a\right)^{2}.

$$8a^{3}+12a^{2}+6a+1-2a\left(4a^{2}+4a+1\right)-2^{2}a^{2}-1$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$8a^{3}+12a^{2}+6a+1-2a\left(4a^{2}+4a+1\right)-4a^{2}-1$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2a ki te 4a^{2}+4a+1.

$$8a^{3}+12a^{2}+6a+1-8a^{3}-8a^{2}-2a-4a^{2}-1$$

Pahekotia te 8a^{3} me -8a^{3}, ka 0.

$$12a^{2}+6a+1-8a^{2}-2a-4a^{2}-1$$

Pahekotia te 12a^{2} me -8a^{2}, ka 4a^{2}.

$$4a^{2}+6a+1-2a-4a^{2}-1$$

Pahekotia te 6a me -2a, ka 4a.

$$4a^{2}+4a+1-4a^{2}-1$$

Pahekotia te 4a^{2} me -4a^{2}, ka 0.

$$4a+1-1$$

Tangohia te 1 i te 1, ka 0.

$$4a$$

Whakaroha

$$4a$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(p+q\right)^{3}=p^{3}+3p^{2}q+3pq^{2}+q^{3} hei whakaroha \left(2a+1\right)^{3}.

$$8a^{3}+12a^{2}+6a+1-2a\left(2a+1\right)^{2}-\left(2a\right)^{2}-1$$

Whakamahia te ture huarua \left(p+q\right)^{2}=p^{2}+2pq+q^{2} hei whakaroha \left(2a+1\right)^{2}.

$$8a^{3}+12a^{2}+6a+1-2a\left(4a^{2}+4a+1\right)-\left(2a\right)^{2}-1$$

Whakarohaina te \left(2a\right)^{2}.

$$8a^{3}+12a^{2}+6a+1-2a\left(4a^{2}+4a+1\right)-2^{2}a^{2}-1$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$8a^{3}+12a^{2}+6a+1-2a\left(4a^{2}+4a+1\right)-4a^{2}-1$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2a ki te 4a^{2}+4a+1.

$$8a^{3}+12a^{2}+6a+1-8a^{3}-8a^{2}-2a-4a^{2}-1$$

Pahekotia te 8a^{3} me -8a^{3}, ka 0.

$$12a^{2}+6a+1-8a^{2}-2a-4a^{2}-1$$

Pahekotia te 12a^{2} me -8a^{2}, ka 4a^{2}.

$$4a^{2}+6a+1-2a-4a^{2}-1$$

Pahekotia te 6a me -2a, ka 4a.

$$4a^{2}+4a+1-4a^{2}-1$$

Pahekotia te 4a^{2} me -4a^{2}, ka 0.

$$4a+1-1$$

Tangohia te 1 i te 1, ka 0.

$$4a$$