Whakaoti i te (2a+1)^2-(2a-2)(2a+2)-5

$$( 2 a + 1 ) ^ { 2 } - ( 2 a - 2 ) ( 2 a + 2 ) - 5$$

Aromātai

$$4a$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(p+q\right)^{2}=p^{2}+2pq+q^{2} hei whakaroha \left(2a+1\right)^{2}.

$$4a^{2}+4a+1-\left(2a-2\right)\left(2a+2\right)-5$$

Whakaarohia te \left(2a-2\right)\left(2a+2\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 2.

$$4a^{2}+4a+1-\left(\left(2a\right)^{2}-4\right)-5$$

Whakarohaina te \left(2a\right)^{2}.

$$4a^{2}+4a+1-\left(2^{2}a^{2}-4\right)-5$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$4a^{2}+4a+1-\left(4a^{2}-4\right)-5$$

Hei kimi i te tauaro o 4a^{2}-4, kimihia te tauaro o ia taurangi.

$$4a^{2}+4a+1-4a^{2}+4-5$$

Pahekotia te 4a^{2} me -4a^{2}, ka 0.

$$4a+1+4-5$$

Tāpirihia te 1 ki te 4, ka 5.

$$4a+5-5$$

Tangohia te 5 i te 5, ka 0.

$$4a$$

Whakaroha

$$4a$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(p+q\right)^{2}=p^{2}+2pq+q^{2} hei whakaroha \left(2a+1\right)^{2}.

$$4a^{2}+4a+1-\left(2a-2\right)\left(2a+2\right)-5$$

Whakaarohia te \left(2a-2\right)\left(2a+2\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Pūrua 2.

$$4a^{2}+4a+1-\left(\left(2a\right)^{2}-4\right)-5$$

Whakarohaina te \left(2a\right)^{2}.

$$4a^{2}+4a+1-\left(2^{2}a^{2}-4\right)-5$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$4a^{2}+4a+1-\left(4a^{2}-4\right)-5$$

Hei kimi i te tauaro o 4a^{2}-4, kimihia te tauaro o ia taurangi.

$$4a^{2}+4a+1-4a^{2}+4-5$$

Pahekotia te 4a^{2} me -4a^{2}, ka 0.

$$4a+1+4-5$$

Tāpirihia te 1 ki te 4, ka 5.

$$4a+5-5$$

Tangohia te 5 i te 5, ka 0.

$$4a$$