Whakaoti i te (2-sqrt{3})*tan60^circ+tan45^circ/1-tan60^circtan45^circ

$$( 2 - \sqrt { 3 } ) \cdot \frac { \tan 60 ^ { \circ } + \tan 45 ^ { \circ } } { 1 - \tan 60 ^ { \circ } \tan 45 ^ { \circ } }$$

Aromātai

$$-1$$

Ngā Upane Otinga

Tīkina te uara \tan(60) mai i te ripanga uara pākoki.

$$\left(2-\sqrt{3}\right)\times \frac{\sqrt{3}+\tan(45)}{1-\tan(60)\tan(45)}$$

Tīkina te uara \tan(45) mai i te ripanga uara pākoki.

$$\left(2-\sqrt{3}\right)\times \frac{\sqrt{3}+1}{1-\tan(60)\tan(45)}$$

Tīkina te uara \tan(60) mai i te ripanga uara pākoki.

$$\left(2-\sqrt{3}\right)\times \frac{\sqrt{3}+1}{1-\sqrt{3}\tan(45)}$$

Tīkina te uara \tan(45) mai i te ripanga uara pākoki.

$$\left(2-\sqrt{3}\right)\times \frac{\sqrt{3}+1}{1-\sqrt{3}\times 1}$$

Tuhia te \left(2-\sqrt{3}\right)\times \frac{\sqrt{3}+1}{1-\sqrt{3}\times 1} hei hautanga kotahi.

$$\frac{\left(2-\sqrt{3}\right)\left(\sqrt{3}+1\right)}{1-\sqrt{3}\times 1}$$

Whakamahia te āhuatanga tuaritanga hei whakarea te 2-\sqrt{3} ki te \sqrt{3}+1 ka whakakotahi i ngā kupu rite.

$$\frac{\sqrt{3}+2-\left(\sqrt{3}\right)^{2}}{1-\sqrt{3}\times 1}$$

Ko te pūrua o \sqrt{3} ko 3.

$$\frac{\sqrt{3}+2-3}{1-\sqrt{3}\times 1}$$

Tangohia te 3 i te 2, ka -1.

$$\frac{\sqrt{3}-1}{1-\sqrt{3}\times 1}$$

Unuhia te tohu tōraro i roto o \sqrt{3}-1.

$$\frac{-\left(-\sqrt{3}+1\right)}{-\sqrt{3}+1}$$

Me whakakore tahi te -\sqrt{3}+1 i te taurunga me te tauraro.

$$-1$$