Whakaoti i te (2-8/x+2):x^2-4x+4/x^2-4

$$( 2 - \frac { 8 } { x + 2 } ) : \frac { x ^ { 2 } - 4 x + 4 } { x ^ { 2 } - 4 }$$

Aromātai

$$2$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 2 ki te \frac{x+2}{x+2}.

$$\frac{\frac{2\left(x+2\right)}{x+2}-\frac{8}{x+2}}{\frac{x^{2}-4x+4}{x^{2}-4}}$$

Tā te mea he rite te tauraro o \frac{2\left(x+2\right)}{x+2} me \frac{8}{x+2}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\frac{2\left(x+2\right)-8}{x+2}}{\frac{x^{2}-4x+4}{x^{2}-4}}$$

Mahia ngā whakarea i roto o 2\left(x+2\right)-8.

$$\frac{\frac{2x+4-8}{x+2}}{\frac{x^{2}-4x+4}{x^{2}-4}}$$

Whakakotahitia ngā kupu rite i 2x+4-8.

$$\frac{\frac{2x-4}{x+2}}{\frac{x^{2}-4x+4}{x^{2}-4}}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea i roto o \frac{x^{2}-4x+4}{x^{2}-4}.

$$\frac{\frac{2x-4}{x+2}}{\frac{\left(x-2\right)^{2}}{\left(x-2\right)\left(x+2\right)}}$$

Me whakakore tahi te x-2 i te taurunga me te tauraro.

$$\frac{\frac{2x-4}{x+2}}{\frac{x-2}{x+2}}$$

Whakawehe \frac{2x-4}{x+2} ki te \frac{x-2}{x+2} mā te whakarea \frac{2x-4}{x+2} ki te tau huripoki o \frac{x-2}{x+2}.

$$\frac{\left(2x-4\right)\left(x+2\right)}{\left(x+2\right)\left(x-2\right)}$$

Me whakakore tahi te x+2 i te taurunga me te tauraro.

$$\frac{2x-4}{x-2}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{2\left(x-2\right)}{x-2}$$

Me whakakore tahi te x-2 i te taurunga me te tauraro.

$$2$$

Tauwehe

$$2$$