Whakaoti i te (2)^2-4(1)(-2k-2)=0

$$( 2 ) ^ { 2 } - 4 ( 1 ) ( - 2 k - 2 ) = 0$$

Whakaoti mō k

$$k = -\frac{3}{2} = -1\frac{1}{2} = -1.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$4-4\times 1\left(-2k-2\right)=0$$

Whakareatia te 4 ki te 1, ka 4.

$$4-4\left(-2k-2\right)=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te -4 ki te -2k-2.

$$4+8k+8=0$$

Tāpirihia te 4 ki te 8, ka 12.

$$12+8k=0$$

Tangohia te 12 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$8k=-12$$

Whakawehea ngā taha e rua ki te 8.

$$k=\frac{-12}{8}$$

Whakahekea te hautanga \frac{-12}{8} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 4.

$$k=-\frac{3}{2}$$