Whakaoti i te (2sqrt{2}-2p)^2-8=0

$$( 2 \sqrt { 2 } - 2 p ) ^ { 2 } - 8 = 0$$

Whakaoti mō p

$$p=0$$

$$p=2\sqrt{2}\approx 2.828427125$$

Ngā Upane Whakamahi Tauwehe

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(2\sqrt{2}-2p\right)^{2}.

$$4\left(\sqrt{2}\right)^{2}-8\sqrt{2}p+4p^{2}-8=0$$

Ko te pūrua o \sqrt{2} ko 2.

$$4\times 2-8\sqrt{2}p+4p^{2}-8=0$$

Whakareatia te 4 ki te 2, ka 8.

$$8-8\sqrt{2}p+4p^{2}-8=0$$

Tangohia te 8 i te 8, ka 0.

$$-8\sqrt{2}p+4p^{2}=0$$

Tauwehea te p.

$$p\left(-8\sqrt{2}+4p\right)=0$$

Hei kimi otinga whārite, me whakaoti te p=0 me te -8\sqrt{2}+4p=0.

$$p=0 p=2\sqrt{2}$$