Whakaoti i te (2^5+sqrt{36})*sqrt{2^2+72:6}=

$$( 2 ^ { 5 } + \sqrt { 36 } ) \cdot \sqrt { 2 ^ { 2 } + 72 : 6 } =$$

Aromātai

$$152$$

Ngā Upane Otinga

Tātaihia te 2 mā te pū o 5, kia riro ko 32.

$$\left(32+\sqrt{36}\right)\sqrt{2^{2}+\frac{72}{6}}$$

Tātaitia te pūtakerua o 36 kia tae ki 6.

$$\left(32+6\right)\sqrt{2^{2}+\frac{72}{6}}$$

Tāpirihia te 32 ki te 6, ka 38.

$$38\sqrt{2^{2}+\frac{72}{6}}$$

Tātaihia te 2 mā te pū o 2, kia riro ko 4.

$$38\sqrt{4+\frac{72}{6}}$$

Whakawehea te 72 ki te 6, kia riro ko 12.

$$38\sqrt{4+12}$$

Tāpirihia te 4 ki te 12, ka 16.

$$38\sqrt{16}$$

Tātaitia te pūtakerua o 16 kia tae ki 4.

$$38\times 4$$

Whakareatia te 38 ki te 4, ka 152.

$$152$$

Tauwehe

$$2^{3}\times 19$$