Whakaoti i te (16*a^-4)^-frac{3{4}}

$$( 16 \cdot a ^ { - 4 } ) ^ { - \frac { 3 } { 4 } }$$

Aromātai

$$\frac{\left(|a|\right)^{3}}{8}$$

Ngā Upane Otinga

Whakarohaina te \left(16a^{-4}\right)^{-\frac{3}{4}}.

$$16^{-\frac{3}{4}}\left(a^{-4}\right)^{-\frac{3}{4}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te -4 me te -\frac{3}{4} kia riro ai te 3.

$$16^{-\frac{3}{4}}a^{3}$$

Tātaihia te 16 mā te pū o -\frac{3}{4}, kia riro ko \frac{1}{8}.

$$\frac{1}{8}a^{3}$$

Kimi Pārōnaki e ai ki a

$$\frac{3a|a|}{8}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$-\frac{3}{4}\times \left(16a^{-4}\right)^{-\frac{3}{4}-1}\frac{\mathrm{d}}{\mathrm{d}a}(16a^{-4})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$-\frac{3}{4}\times \left(16a^{-4}\right)^{-\frac{7}{4}}\left(-4\right)\times 16a^{-4-1}$$

Whakarūnātia.

$$48a^{-5}\times \left(16a^{-4}\right)^{-\frac{7}{4}}$$