Whakaoti i te (110)^n=1/3855

$$( 110 ) ^ { n } = \frac { 1 } { 3855 }$$

Whakaoti mō n

$$n=-\log_{110}\left(3855\right)\approx -1.75665584$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.

$$110^{n}=\frac{1}{3855}$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(110^{n})=\log(\frac{1}{3855})$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$n\log(110)=\log(\frac{1}{3855})$$

Whakawehea ngā taha e rua ki te \log(110).

$$n=\frac{\log(\frac{1}{3855})}{\log(110)}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$n=\log_{110}\left(\frac{1}{3855}\right)$$