Whakaoti i te (10-sqrt{2}c+12)*(frac{sqrt{2}}{2}c+10)*1/2

$$( 10 - \sqrt { 2 } c + 12 ) \times ( \frac { \sqrt { 2 } } { 2 } c + 10 ) \times \frac { 1 } { 2 }$$

Aromātai

$$\frac{-c^{2}+\sqrt{2}c+220}{2}$$

Ngā Hipanga Rongoā Poto

Tuhia te \frac{\sqrt{2}}{2}c hei hautanga kotahi.

$$\left(10-\sqrt{2}c+12\right)\left(\frac{\sqrt{2}c}{2}+10\right)\times \frac{1}{2}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia 10 ki te \frac{2}{2}.

$$\left(10-\sqrt{2}c+12\right)\left(\frac{\sqrt{2}c}{2}+\frac{10\times 2}{2}\right)\times \frac{1}{2}$$

Tā te mea he rite te tauraro o \frac{\sqrt{2}c}{2} me \frac{10\times 2}{2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\left(10-\sqrt{2}c+12\right)\times \frac{\sqrt{2}c+10\times 2}{2}\times \frac{1}{2}$$

Mahia ngā whakarea i roto o \sqrt{2}c+10\times 2.

$$\left(10-\sqrt{2}c+12\right)\times \frac{\sqrt{2}c+20}{2}\times \frac{1}{2}$$

Tuhia te \left(10-\sqrt{2}c+12\right)\times \frac{\sqrt{2}c+20}{2} hei hautanga kotahi.

$$\frac{\left(10-\sqrt{2}c+12\right)\left(\sqrt{2}c+20\right)}{2}\times \frac{1}{2}$$

Me whakarea te \frac{\left(10-\sqrt{2}c+12\right)\left(\sqrt{2}c+20\right)}{2} ki te \frac{1}{2} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(10-\sqrt{2}c+12\right)\left(\sqrt{2}c+20\right)}{2\times 2}$$

Whakareatia te 2 ki te 2, ka 4.

$$\frac{\left(10-\sqrt{2}c+12\right)\left(\sqrt{2}c+20\right)}{4}$$

Tāpirihia te 10 ki te 12, ka 22.

$$\frac{\left(22-\sqrt{2}c\right)\left(\sqrt{2}c+20\right)}{4}$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o 22-\sqrt{2}c ki ia tau o \sqrt{2}c+20.

$$\frac{22\sqrt{2}c+440-\left(\sqrt{2}\right)^{2}c^{2}-20c\sqrt{2}}{4}$$

Ko te pūrua o \sqrt{2} ko 2.

$$\frac{22\sqrt{2}c+440-2c^{2}-20c\sqrt{2}}{4}$$

Pahekotia te 22\sqrt{2}c me -20c\sqrt{2}, ka 2\sqrt{2}c.

$$\frac{2\sqrt{2}c+440-2c^{2}}{4}$$

Tauwehe

$$\frac{-c^{2}+\sqrt{2}c+220}{2}$$