Whakaoti i te (10*x+y)=5x(x+y)

$$( 10 * x + y ) = 5 x ( x + y )$$

Whakaoti mō y

$$y=-\frac{5x\left(2-x\right)}{1-5x}$$

$$x\neq \frac{1}{5}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 5x ki te x+y.

$$10x+y=5x^{2}+5xy$$

Tangohia te 5xy mai i ngā taha e rua.

$$10x+y-5xy=5x^{2}$$

Tangohia te 10x mai i ngā taha e rua.

$$y-5xy=5x^{2}-10x$$

Pahekotia ngā kīanga tau katoa e whai ana i te y.

$$\left(1-5x\right)y=5x^{2}-10x$$

Whakawehea ngā taha e rua ki te 1-5x.

$$\frac{\left(1-5x\right)y}{1-5x}=\frac{5x\left(x-2\right)}{1-5x}$$

Mā te whakawehe ki te 1-5x ka wetekia te whakareanga ki te 1-5x.

$$y=\frac{5x\left(x-2\right)}{1-5x}$$

Whakaoti mō x

$$x=-\frac{\sqrt{25y^{2}-80y+100}}{10}-\frac{y}{2}+1$$

$$x=\frac{\sqrt{25y^{2}-80y+100}}{10}-\frac{y}{2}+1$$