Whakaoti i te (1.2-4/5)^-2+sqrt{25/16}-2^-1=

$$( 1.2 - \frac { 4 } { 5 } ) ^ { - 2 } + \sqrt { \frac { 25 } { 16 } } - 2 ^ { - 1 } =$$

Aromātai

$$7$$

Ngā Upane Otinga

Tangohia te \frac{4}{5} i te 1.2, ka \frac{2}{5}.

$$\left(\frac{2}{5}\right)^{-2}+\sqrt{\frac{25}{16}}-2^{-1}$$

Tātaihia te \frac{2}{5} mā te pū o -2, kia riro ko \frac{25}{4}.

$$\frac{25}{4}+\sqrt{\frac{25}{16}}-2^{-1}$$

Tuhia anō te pūtake rua o te whakawehenga \frac{25}{16} hei whakawehenga o ngā pūtake rua \frac{\sqrt{25}}{\sqrt{16}}. Tuhia te pūtakerua o te taurunga me te tauraro.

$$\frac{25}{4}+\frac{5}{4}-2^{-1}$$

Tāpirihia te \frac{25}{4} ki te \frac{5}{4}, ka \frac{15}{2}.

$$\frac{15}{2}-2^{-1}$$

Tātaihia te 2 mā te pū o -1, kia riro ko \frac{1}{2}.

$$\frac{15}{2}-\frac{1}{2}$$

Tangohia te \frac{1}{2} i te \frac{15}{2}, ka 7.

$$7$$

Tauwehe

$$7$$