Whakaoti i te (1-k)x^2+x+(1-k)=0t

$$( 1 - k ) x ^ { 2 } + x + ( 1 - k ) = 0 t$$

Whakaoti mō k

$$k=\frac{x^{2}+x+1}{x^{2}+1}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 1-k ki te x^{2}.

$$x^{2}-kx^{2}+x+1-k=0t$$

Ko te tau i whakarea ki te kore ka hua ko te kore.

$$x^{2}-kx^{2}+x+1-k=0$$

Tangohia te x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-kx^{2}+x+1-k=-x^{2}$$

Tangohia te x mai i ngā taha e rua.

$$-kx^{2}+1-k=-x^{2}-x$$

Tangohia te 1 mai i ngā taha e rua.

$$-kx^{2}-k=-x^{2}-x-1$$

Pahekotia ngā kīanga tau katoa e whai ana i te k.

$$\left(-x^{2}-1\right)k=-x^{2}-x-1$$

Whakawehea ngā taha e rua ki te -x^{2}-1.

$$\frac{\left(-x^{2}-1\right)k}{-x^{2}-1}=\frac{-x^{2}-x-1}{-x^{2}-1}$$

Mā te whakawehe ki te -x^{2}-1 ka wetekia te whakareanga ki te -x^{2}-1.

$$k=\frac{-x^{2}-x-1}{-x^{2}-1}$$

Whakawehe -x^{2}-x-1 ki te -x^{2}-1.

$$k=\frac{x^{2}+x+1}{x^{2}+1}$$

Whakaoti mō t

$$t\in \mathrm{R}$$

$$k=\frac{x^{2}+x+1}{x^{2}+1}$$