Whakaoti i te (1-2x)(1-3x)=(6x-1)x-1

$$( 1 - 2 x ) ( 1 - 3 x ) = ( 6 x - 1 ) x - 1$$

Whakaoti mō x

$$x=\frac{1}{2}=0.5$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tuaritanga hei whakarea te 1-2x ki te 1-3x ka whakakotahi i ngā kupu rite.

$$1-5x+6x^{2}=\left(6x-1\right)x-1$$

Whakamahia te āhuatanga tohatoha hei whakarea te 6x-1 ki te x.

$$1-5x+6x^{2}=6x^{2}-x-1$$

Tangohia te 6x^{2} mai i ngā taha e rua.

$$1-5x+6x^{2}-6x^{2}=-x-1$$

Pahekotia te 6x^{2} me -6x^{2}, ka 0.

$$1-5x=-x-1$$

Me tāpiri te x ki ngā taha e rua.

$$1-5x+x=-1$$

Pahekotia te -5x me x, ka -4x.

$$1-4x=-1$$

Tangohia te 1 mai i ngā taha e rua.

$$-4x=-1-1$$

Tangohia te 1 i te -1, ka -2.

$$-4x=-2$$

Whakawehea ngā taha e rua ki te -4.

$$x=\frac{-2}{-4}$$

Whakahekea te hautanga \frac{-2}{-4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -2.

$$x=\frac{1}{2}$$