Whakaoti i te (1+2x)^1/2 | Kairarau Microsoft

Kimi Pārōnaki e ai ki x

Aromātai

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Pātaitai

Algebra

5 raruraru e ōrite ana ki:

Ngā Raru Ōrite mai i te Rapu Tukutuku

https://socratic.org/questions/what-is-the-limit-of-1-2x-1-x-as-x-approaches-infinity

https://socratic.org/questions/what-is-the-derivative-of-3-2x-1-2

https://math.stackexchange.com/questions/1297799/find-a-formula-for-the-binomial-coefficients-of-the-macluarin-series-for-frac

https://math.stackexchange.com/questions/82428/using-the-taylor-expansion-for-1x-1-2-evaluate-sum-n-0-infty-bi

https://math.stackexchange.com/questions/2954152/find-the-binomial-expansion-of-the-function-up-to-the-first-3-non-zero-terms-s

Tohaina

Kua tāruatia ki te papatopenga

\frac{1}{2}\left(2x^{1}+1\right)^{\frac{1}{2}-1}\frac{\mathrm{d}}{\mathrm{d}x}(2x^{1}+1)

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

\frac{1}{2}\left(2x^{1}+1\right)^{-\frac{1}{2}}\times 2x^{1-1}

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

x^{0}\left(2x^{1}+1\right)^{-\frac{1}{2}}

Whakarūnātia.

x^{0}\left(2x+1\right)^{-\frac{1}{2}}

Mō tētahi kupu t, t^{1}=t.

1\left(2x+1\right)^{-\frac{1}{2}}

Mō tētahi kupu t mahue te 0, t^{0}=1.

\left(2x+1\right)^{-\frac{1}{2}}

Mō tētahi kupu t, t\times 1=t me 1t=t.