Whakaoti i te (0)^6*(1)^6-[(1)^2]^3=

$$( 0 ) ^ { 6 } \cdot ( 1 ) ^ { 6 } - [ ( 1 ) ^ { 2 } ] ^ { 3 } =$$

Aromātai

$$-1$$

Ngā Upane Otinga

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 2 me te 3 kia riro ai te 6.

$$0^{6}\times 1^{6}-1^{6}$$

Tātaihia te 0 mā te pū o 6, kia riro ko 0.

$$0\times 1^{6}-1^{6}$$

Tātaihia te 1 mā te pū o 6, kia riro ko 1.

$$0\times 1-1^{6}$$

Whakareatia te 0 ki te 1, ka 0.

$$0-1^{6}$$

Tātaihia te 1 mā te pū o 6, kia riro ko 1.

$$0-1$$

Tangohia te 1 i te 0, ka -1.

$$-1$$

Tauwehe

$$-1$$