Whakaoti i te (-8+4x^{2}+4xy^2)+(9x^3-x^2+xy^2)

$$( - 8 + 4 x ^ { 2 } + 4 x y ^ { 2 } ) + ( 9 x ^ { 3 } - x ^ { 2 } + x y ^ { 2 } )$$

Kimi Pārōnaki e ai ki x

$$27x^{2}+6x+5y^{2}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te 4x^{2} me -x^{2}, ka 3x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-8+3x^{2}+4xy^{2}+9x^{3}+xy^{2})$$

Pahekotia te 4xy^{2} me xy^{2}, ka 5xy^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-8+3x^{2}+5xy^{2}+9x^{3})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2\times 3x^{2-1}+5y^{2}x^{1-1}+3\times 9x^{3-1}$$

Whakareatia 2 ki te 3.

$$6x^{2-1}+5y^{2}x^{1-1}+3\times 9x^{3-1}$$

Tango 1 mai i 2.

$$6x^{1}+5y^{2}x^{1-1}+3\times 9x^{3-1}$$

Tango 1 mai i 1.

$$6x^{1}+5y^{2}x^{0}+3\times 9x^{3-1}$$

Whakareatia 1 ki te 5y^{2}.

$$6x^{1}+5y^{2}x^{0}+27x^{3-1}$$

Tango 1 mai i 3.

$$6x^{1}+5y^{2}x^{0}+27x^{2}$$

Mō tētahi kupu t, t^{1}=t.

$$6x+5y^{2}x^{0}+27x^{2}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$6x+5y^{2}\times 1+27x^{2}$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$6x+5y^{2}+27x^{2}$$

Aromātai

$$9x^{3}+3x^{2}+5xy^{2}-8$$