Whakaoti i te (-5+8a^3)^2=I

$$( - 5 + 8 a ^ { 3 } ) ^ { 2 } = I$$

Whakaoti mō I

$$I=\left(8a^{3}-5\right)^{2}$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(p+q\right)^{2}=p^{2}+2pq+q^{2} hei whakaroha \left(-5+8a^{3}\right)^{2}.

$$25-80a^{3}+64\left(a^{3}\right)^{2}=I$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 3 me te 2 kia riro ai te 6.

$$25-80a^{3}+64a^{6}=I$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$I=25-80a^{3}+64a^{6}$$

Whakaoti mō a

$$a=\frac{\sqrt[3]{-\sqrt{I}+5}}{2}$$

$$a=\frac{\sqrt[3]{\sqrt{I}+5}}{2}\text{, }I\geq 0$$