Whakaoti i te (-4)^2-4(-1)(-k+2)=0

$$( - 4 ) ^ { 2 } - 4 ( - 1 ) ( - k + 2 ) = 0$$

Whakaoti mō k

$$k=6$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tātaihia te -4 mā te pū o 2, kia riro ko 16.

$$16-4\left(-1\right)\left(-k+2\right)=0$$

Whakareatia te 4 ki te -1, ka -4.

$$16-\left(-4\left(-k+2\right)\right)=0$$

Ko te tauaro o -4\left(-k+2\right) ko 4\left(-k+2\right).

$$16+4\left(-k+2\right)=0$$

Whakamahia te āhuatanga tohatoha hei whakarea te 4 ki te -k+2.

$$16+4\left(-k\right)+8=0$$

Tāpirihia te 16 ki te 8, ka 24.

$$24+4\left(-k\right)=0$$

Tangohia te 24 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$4\left(-k\right)=-24$$

Whakawehea ngā taha e rua ki te 4.

$$-k=\frac{-24}{4}$$

Whakawehea te -24 ki te 4, kia riro ko -6.

$$-k=-6$$

Me whakarea ngā taha e rua ki te -1.

$$k=6$$