Whakaoti i te (-41/20)*(-1.25)=(-1/2)^3=(-10)*(-1/3)^5*(-0.1^2)

$$( - 4 \frac { 1 } { 20 } ) \times ( - 1.25 ) = ( - \frac { 1 } { 2 } ) ^ { 3 } = ( - 10 ) \times ( - \frac { 1 } { 3 } ) ^ { 5 } \times ( - 0.1 ^ { 2 } )$$

Manatoko

Ngā Upane Otinga

Whakareatia te 4 ki te 20, ka 80.

$$\left(-\frac{80+1}{20}\right)\left(-1.25\right)=\left(-\frac{1}{2}\right)^{3}\text{ and }\left(-\frac{1}{2}\right)^{3}=-10\left(-\frac{1}{3}\right)^{5}\left(-0.1^{2}\right)$$

Tāpirihia te 80 ki te 1, ka 81.

$$-\frac{81}{20}\left(-1.25\right)=\left(-\frac{1}{2}\right)^{3}\text{ and }\left(-\frac{1}{2}\right)^{3}=-10\left(-\frac{1}{3}\right)^{5}\left(-0.1^{2}\right)$$

Me tahuri ki tau ā-ira -1.25 ki te hautau -\frac{125}{100}. Whakahekea te hautanga -\frac{125}{100} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 25.

$$-\frac{81}{20}\left(-\frac{5}{4}\right)=\left(-\frac{1}{2}\right)^{3}\text{ and }\left(-\frac{1}{2}\right)^{3}=-10\left(-\frac{1}{3}\right)^{5}\left(-0.1^{2}\right)$$

Me whakarea te -\frac{81}{20} ki te -\frac{5}{4} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{-81\left(-5\right)}{20\times 4}=\left(-\frac{1}{2}\right)^{3}\text{ and }\left(-\frac{1}{2}\right)^{3}=-10\left(-\frac{1}{3}\right)^{5}\left(-0.1^{2}\right)$$

Mahia ngā whakarea i roto i te hautanga \frac{-81\left(-5\right)}{20\times 4}.

$$\frac{405}{80}=\left(-\frac{1}{2}\right)^{3}\text{ and }\left(-\frac{1}{2}\right)^{3}=-10\left(-\frac{1}{3}\right)^{5}\left(-0.1^{2}\right)$$

Whakahekea te hautanga \frac{405}{80} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 5.

$$\frac{81}{16}=\left(-\frac{1}{2}\right)^{3}\text{ and }\left(-\frac{1}{2}\right)^{3}=-10\left(-\frac{1}{3}\right)^{5}\left(-0.1^{2}\right)$$

Tātaihia te -\frac{1}{2} mā te pū o 3, kia riro ko -\frac{1}{8}.

$$\frac{81}{16}=-\frac{1}{8}\text{ and }\left(-\frac{1}{2}\right)^{3}=-10\left(-\frac{1}{3}\right)^{5}\left(-0.1^{2}\right)$$

Ko te maha noa iti rawa atu o 16 me 8 ko 16. Me tahuri \frac{81}{16} me -\frac{1}{8} ki te hautau me te tautūnga 16.

$$\frac{81}{16}=-\frac{2}{16}\text{ and }\left(-\frac{1}{2}\right)^{3}=-10\left(-\frac{1}{3}\right)^{5}\left(-0.1^{2}\right)$$

Whakatauritea te \frac{81}{16} me te -\frac{2}{16}.

$$\text{false}\text{ and }\left(-\frac{1}{2}\right)^{3}=-10\left(-\frac{1}{3}\right)^{5}\left(-0.1^{2}\right)$$

Tātaihia te -\frac{1}{2} mā te pū o 3, kia riro ko -\frac{1}{8}.

$$\text{false}\text{ and }-\frac{1}{8}=-10\left(-\frac{1}{3}\right)^{5}\left(-0.1^{2}\right)$$

Tātaihia te -\frac{1}{3} mā te pū o 5, kia riro ko -\frac{1}{243}.

$$\text{false}\text{ and }-\frac{1}{8}=-10\left(-\frac{1}{243}\right)\left(-0.1^{2}\right)$$

Tuhia te -10\left(-\frac{1}{243}\right) hei hautanga kotahi.

$$\text{false}\text{ and }-\frac{1}{8}=\frac{-10\left(-1\right)}{243}\left(-0.1^{2}\right)$$

Whakareatia te -10 ki te -1, ka 10.

$$\text{false}\text{ and }-\frac{1}{8}=\frac{10}{243}\left(-0.1^{2}\right)$$

Tātaihia te 0.1 mā te pū o 2, kia riro ko 0.01.

$$\text{false}\text{ and }-\frac{1}{8}=\frac{10}{243}\left(-0.01\right)$$

Me tahuri ki tau ā-ira -0.01 ki te hautau -\frac{1}{100}.

$$\text{false}\text{ and }-\frac{1}{8}=\frac{10}{243}\left(-\frac{1}{100}\right)$$

Me whakarea te \frac{10}{243} ki te -\frac{1}{100} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\text{false}\text{ and }-\frac{1}{8}=\frac{10\left(-1\right)}{243\times 100}$$

Mahia ngā whakarea i roto i te hautanga \frac{10\left(-1\right)}{243\times 100}.

$$\text{false}\text{ and }-\frac{1}{8}=\frac{-10}{24300}$$

Whakahekea te hautanga \frac{-10}{24300} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 10.

$$\text{false}\text{ and }-\frac{1}{8}=-\frac{1}{2430}$$

Ko te maha noa iti rawa atu o 8 me 2430 ko 9720. Me tahuri -\frac{1}{8} me -\frac{1}{2430} ki te hautau me te tautūnga 9720.

$$\text{false}\text{ and }-\frac{1215}{9720}=-\frac{4}{9720}$$

Whakatauritea te -\frac{1215}{9720} me te -\frac{4}{9720}.

$$\text{false}\text{ and }\text{false}$$

Ko te kōmititanga tōrunga o \text{false} me \text{false} ko \text{false}.

$$\text{false}$$