Whakaoti i te (-3)(2)^n-1=-1536

$$( - 3 ) ( 2 ) ^ { n - 1 } = - 1536$$

Whakaoti mō n

$$n=10$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Taupū Kōaro

Whakawehea ngā taha e rua ki te -3.

$$2^{n-1}=\frac{-1536}{-3}$$

Whakawehea te -1536 ki te -3, kia riro ko 512.

$$2^{n-1}=512$$

Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.

$$\log(2^{n-1})=\log(512)$$

Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.

$$\left(n-1\right)\log(2)=\log(512)$$

Whakawehea ngā taha e rua ki te \log(2).

$$n-1=\frac{\log(512)}{\log(2)}$$

Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$n-1=\log_{2}\left(512\right)$$

Me tāpiri 1 ki ngā taha e rua o te whārite.

$$n=9-\left(-1\right)$$