Whakaoti i te (-3sqrt{2/3})^2

$$( - 3 \sqrt { \frac { 2 } { 3 } } ) ^ { 2 }$$

Aromātai

$$6$$

Ngā Upane Otinga

Tuhia anō te pūtake rua o te whakawehenga \sqrt{\frac{2}{3}} hei whakawehenga o ngā pūtake rua \frac{\sqrt{2}}{\sqrt{3}}.

$$\left(-3\times \frac{\sqrt{2}}{\sqrt{3}}\right)^{2}$$

Whakangāwaritia te tauraro o \frac{\sqrt{2}}{\sqrt{3}} mā te whakarea i te taurunga me te tauraro ki te \sqrt{3}.

$$\left(-3\times \frac{\sqrt{2}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}\right)^{2}$$

Ko te pūrua o \sqrt{3} ko 3.

$$\left(-3\times \frac{\sqrt{2}\sqrt{3}}{3}\right)^{2}$$

Hei whakarea \sqrt{2} me \sqrt{3}, whakareatia ngā tau i raro i te pūtake rua.

$$\left(-3\times \frac{\sqrt{6}}{3}\right)^{2}$$

Me whakakore te 3 me te 3.

$$\left(-\sqrt{6}\right)^{2}$$

Whakarohaina te \left(-\sqrt{6}\right)^{2}.

$$\left(-1\right)^{2}\left(\sqrt{6}\right)^{2}$$

Tātaihia te -1 mā te pū o 2, kia riro ko 1.

$$1\left(\sqrt{6}\right)^{2}$$

Ko te pūrua o \sqrt{6} ko 6.

$$1\times 6$$

Whakareatia te 1 ki te 6, ka 6.

$$6$$

Tauwehe

$$2\times 3$$