Whakaoti i te (-2)^3-|-1/2|+(1/3)^-2div(3-pi)^0

$$( - 2 ) ^ { 3 } - | - \frac { 1 } { 2 } | + ( \frac { 1 } { 3 } ) ^ { - 2 } \div ( 3 - \pi ) ^ { 0 }$$

Aromātai

$$\frac{1}{2}=0.5$$

Ngā Hipanga Rongoā Poto

Tātaihia te -2 mā te pū o 3, kia riro ko -8.

$$-8-|-\frac{1}{2}|+\frac{\left(\frac{1}{3}\right)^{-2}}{\left(3-\pi \right)^{0}}$$

Ko te uara pū o tētahi tau tūturu a ko a ina a\geq 0, ko -a rānei ina a<0. Ko te uara pū o -\frac{1}{2} ko \frac{1}{2}.

$$-8-\frac{1}{2}+\frac{\left(\frac{1}{3}\right)^{-2}}{\left(3-\pi \right)^{0}}$$

Tangohia te \frac{1}{2} i te -8, ka -\frac{17}{2}.

$$-\frac{17}{2}+\frac{\left(\frac{1}{3}\right)^{-2}}{\left(3-\pi \right)^{0}}$$

Tātaihia te \frac{1}{3} mā te pū o -2, kia riro ko 9.

$$-\frac{17}{2}+\frac{9}{\left(3-\pi \right)^{0}}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 2 me \left(3-\pi \right)^{0} ko 2. Whakareatia \frac{9}{\left(3-\pi \right)^{0}} ki te \frac{2}{2}.

$$-\frac{17}{2}+\frac{9\times 2}{2}$$

Tā te mea he rite te tauraro o -\frac{17}{2} me \frac{9\times 2}{2}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{-17+9\times 2}{2}$$

Mahia ngā whakarea i roto o -17+9\times 2.

$$\frac{-17+18}{2}$$

Mahia ngā tātaitai i roto o -17+18.

$$\frac{1}{2}$$

Tauwehe

$$\frac{1}{2} = 0.5$$