Whakaoti i te (-18a^2b^2):(-6ab^2)

$$( - 18 a ^ { 2 } b ^ { 2 } ) : ( - 6 a b ^ { 2 } )$$

Aromātai

$$3a$$

Ngā Upane e Whakamahi ana i te Āhuatanga o te Otinga o ngā Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\frac{\left(-18\right)^{1}a^{2}b^{2}}{\left(-6\right)^{1}a^{1}b^{2}}$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\left(-18\right)^{1}}{\left(-6\right)^{1}}a^{2-1}b^{2-2}$$

Tango 1 mai i 2.

$$\frac{\left(-18\right)^{1}}{\left(-6\right)^{1}}a^{1}b^{2-2}$$

Tango 2 mai i 2.

$$\frac{\left(-18\right)^{1}}{\left(-6\right)^{1}}ab^{0}$$

Mō tētahi tau a mahue te 0, a^{0}=1.

$$\frac{\left(-18\right)^{1}}{\left(-6\right)^{1}}a$$

Whakawehe -18 ki te -6.

$$3a$$

Kimi Pārōnaki e ai ki a

$$3$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}a}(\left(-\frac{18b^{2}}{-6b^{2}}\right)a^{2-1})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}a}(3a^{1})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3a^{1-1}$$

Mahia ngā tātaitanga.

$$3a^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$3\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$3$$