Whakaoti i te (-1)(1+sqrt{2})quad(16)(2-sqrt{8})

$$( - 1 ) ( 1 + \sqrt { 2 } ) \quad ( 16 ) ( 2 - \sqrt { 8 } )$$

Aromātai

$$32$$

Ngā Upane Otinga

Whakareatia te -1 ki te 16, ka -16.

$$-16\left(1+\sqrt{2}\right)\left(2-\sqrt{8}\right)$$

Tauwehea te 8=2^{2}\times 2. Tuhia anō te pūtake rua o te hua \sqrt{2^{2}\times 2} hei hua o ngā pūtake rua \sqrt{2^{2}}\sqrt{2}. Tuhia te pūtakerua o te 2^{2}.

$$-16\left(1+\sqrt{2}\right)\left(2-2\sqrt{2}\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -16 ki te 1+\sqrt{2}.

$$\left(-16-16\sqrt{2}\right)\left(2-2\sqrt{2}\right)$$

Me hoatu te āhuatanga tohatoha mā te whakarea ia tau o -16-16\sqrt{2} ki ia tau o 2-2\sqrt{2}.

$$-32+32\sqrt{2}-32\sqrt{2}+32\left(\sqrt{2}\right)^{2}$$

Pahekotia te 32\sqrt{2} me -32\sqrt{2}, ka 0.

$$-32+32\left(\sqrt{2}\right)^{2}$$

Ko te pūrua o \sqrt{2} ko 2.

$$-32+32\times 2$$

Whakareatia te 32 ki te 2, ka 64.

$$-32+64$$

Tāpirihia te -32 ki te 64, ka 32.

$$32$$

Tauwehe

$$2^{5}$$