Whakaoti i te (-7/3x^3)*(-4/7x)+2/3x^4=

$$( - \frac { 7 } { 3 } x ^ { 3 } ) \cdot ( - \frac { 4 } { 7 } x ) + \frac { 2 } { 3 } x ^ { 4 } =$$

Aromātai

$$2x^{4}$$

Ngā Upane Otinga

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 3 me te 1 kia riro ai te 4.

$$-\frac{7}{3}x^{4}\left(-\frac{4}{7}\right)+\frac{2}{3}x^{4}$$

Whakareatia te -\frac{7}{3} ki te -\frac{4}{7}, ka \frac{4}{3}.

$$\frac{4}{3}x^{4}+\frac{2}{3}x^{4}$$

Pahekotia te \frac{4}{3}x^{4} me \frac{2}{3}x^{4}, ka 2x^{4}.

$$2x^{4}$$

Kimi Pārōnaki e ai ki x

$$8x^{3}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\left(-\left(-\frac{4x}{3}\right)\right)x^{3-1}+4\times \frac{2}{3}x^{4-1}$$

Whakareatia 3 ki te -\frac{7}{3}\left(-\frac{4}{7}\right)x.

$$4xx^{3-1}+4\times \frac{2}{3}x^{4-1}$$

Tango 1 mai i 3.

$$4xx^{2}+4\times \frac{2}{3}x^{4-1}$$

Whakareatia 4 ki te \frac{2}{3}.

$$4xx^{2}+\frac{8}{3}x^{4-1}$$

Tango 1 mai i 4.

$$4xx^{2}+\frac{8}{3}x^{3}$$