Whakaoti i te (x^3+4x^2-10x+7)+(-6x^3+5x-10)

$$( { x }^{ 3 } +4 { x }^{ 2 } -10x+7)+(-6 { x }^{ 3 } +5x-10)$$

Aromātai

$$-5x^{3}+4x^{2}-5x-3$$

Ngā Upane Otinga

Pahekotia te x^{3} me -6x^{3}, ka -5x^{3}.

$$-5x^{3}+4x^{2}-10x+7+5x-10$$

Pahekotia te -10x me 5x, ka -5x.

$$-5x^{3}+4x^{2}-5x+7-10$$

Tangohia te 10 i te 7, ka -3.

$$-5x^{3}+4x^{2}-5x-3$$

Kimi Pārōnaki e ai ki x

$$-15x^{2}+8x-5$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te x^{3} me -6x^{3}, ka -5x^{3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-5x^{3}+4x^{2}-10x+7+5x-10)$$

Pahekotia te -10x me 5x, ka -5x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-5x^{3}+4x^{2}-5x+7-10)$$

Tangohia te 10 i te 7, ka -3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-5x^{3}+4x^{2}-5x-3)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$3\left(-5\right)x^{3-1}+2\times 4x^{2-1}-5x^{1-1}$$

Whakareatia 3 ki te -5.

$$-15x^{3-1}+2\times 4x^{2-1}-5x^{1-1}$$

Tango 1 mai i 3.

$$-15x^{2}+2\times 4x^{2-1}-5x^{1-1}$$

Whakareatia 2 ki te 4.

$$-15x^{2}+8x^{2-1}-5x^{1-1}$$

Tango 1 mai i 2.

$$-15x^{2}+8x^{1}-5x^{1-1}$$

Tango 1 mai i 1.

$$-15x^{2}+8x^{1}-5x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$-15x^{2}+8x-5x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$-15x^{2}+8x-5$$