Whakaoti i te (x^2-8x-2)+(4x-3)

$$( { x }^{ 2 } -8x-2)+(4x-3)$$

Aromātai

$$\left(x-5\right)\left(x+1\right)$$

Ngā Upane Otinga

Pahekotia te -8x me 4x, ka -4x.

$$x^{2}-4x-2-3$$

Tangohia te 3 i te -2, ka -5.

$$x^{2}-4x-5$$

Tauwehe

$$\left(x-5\right)\left(x+1\right)$$

Ngā Upane Otinga

Whakarea ka paheko i ngā kīanga tau ōrite.

$$x^{2}-4x-5$$

Whakatauwehea te kīanga mā te whakarōpū. Tuatahi, me tuhi anō te kīanga hei x^{2}+ax+bx-5. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=-4 ab=1\left(-5\right)=-5$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōraro te a+b, he nui ake te uara pū o te tau tōraro i tō te tōrunga. Ko te takirua anake pērā ko te otinga pūnaha.

$$a=-5 b=1$$

Tuhia anō te x^{2}-4x-5 hei \left(x^{2}-5x\right)+\left(x-5\right).

$$\left(x^{2}-5x\right)+\left(x-5\right)$$

Whakatauwehea atu x i te x^{2}-5x.

$$x\left(x-5\right)+x-5$$

Whakatauwehea atu te kīanga pātahi x-5 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(x-5\right)\left(x+1\right)$$