Whakaoti i te (sqrt{x}-sqrt{2})(sqrt{x}+sqrt{2})

$$( \sqrt { x } - \sqrt { 2 } ) ( \sqrt { x } + \sqrt { 2 } )$$

Aromātai

$$x-2$$

Ngā Upane Otinga

Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\left(\sqrt{x}\right)^{2}-\left(\sqrt{2}\right)^{2}$$

Tātaihia te \sqrt{x} mā te pū o 2, kia riro ko x.

$$x-\left(\sqrt{2}\right)^{2}$$

Ko te pūrua o \sqrt{2} ko 2.

$$x-2$$

Kimi Pārōnaki e ai ki x

$$1$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Whakaarohia te \left(\sqrt{x}-\sqrt{2}\right)\left(\sqrt{x}+\sqrt{2}\right). Ka taea te whakareanga te panoni ki te rerekētanga o ngā pūrua mā te ture: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\left(\sqrt{x}\right)^{2}-\left(\sqrt{2}\right)^{2})$$

Tātaihia te \sqrt{x} mā te pū o 2, kia riro ko x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-\left(\sqrt{2}\right)^{2})$$

Ko te pūrua o \sqrt{2} ko 2.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x-2)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$x^{1-1}$$

Tango 1 mai i 1.

$$x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$1$$