Whakaoti i te (sqrt{10}-sqrt{2})^2

$$( \sqrt { 10 } - \sqrt { 2 } ) ^ { 2 }$$

Aromātai

$$12-4\sqrt{5}\approx 3.05572809$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(\sqrt{10}-\sqrt{2}\right)^{2}.

$$\left(\sqrt{10}\right)^{2}-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Ko te pūrua o \sqrt{10} ko 10.

$$10-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Tauwehea te 10=2\times 5. Tuhia anō te pūtake rua o te hua \sqrt{2\times 5} hei hua o ngā pūtake rua \sqrt{2}\sqrt{5}.

$$10-2\sqrt{2}\sqrt{5}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Whakareatia te \sqrt{2} ki te \sqrt{2}, ka 2.

$$10-2\times 2\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Whakareatia te -2 ki te 2, ka -4.

$$10-4\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Ko te pūrua o \sqrt{2} ko 2.

$$10-4\sqrt{5}+2$$

Tāpirihia te 10 ki te 2, ka 12.

$$12-4\sqrt{5}$$

Whakaroha

$$12-4\sqrt{5}$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(a-b\right)^{2}=a^{2}-2ab+b^{2} hei whakaroha \left(\sqrt{10}-\sqrt{2}\right)^{2}.

$$\left(\sqrt{10}\right)^{2}-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Ko te pūrua o \sqrt{10} ko 10.

$$10-2\sqrt{10}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Tauwehea te 10=2\times 5. Tuhia anō te pūtake rua o te hua \sqrt{2\times 5} hei hua o ngā pūtake rua \sqrt{2}\sqrt{5}.

$$10-2\sqrt{2}\sqrt{5}\sqrt{2}+\left(\sqrt{2}\right)^{2}$$

Whakareatia te \sqrt{2} ki te \sqrt{2}, ka 2.

$$10-2\times 2\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Whakareatia te -2 ki te 2, ka -4.

$$10-4\sqrt{5}+\left(\sqrt{2}\right)^{2}$$

Ko te pūrua o \sqrt{2} ko 2.

$$10-4\sqrt{5}+2$$

Tāpirihia te 10 ki te 2, ka 12.

$$12-4\sqrt{5}$$