Whakaoti i te (sqrt{1-019}+03^2-6/25)*(-3)

$$( \sqrt { 1 - 019 } + 03 ^ { 2 } - \frac { 6 } { 25 } ) \cdot ( - 3 )$$

Aromātai

$$-\frac{57}{25}=-2.28$$

Ngā Upane Otinga

Whakareatia te 0 ki te 19, ka 0.

$$\left(\sqrt{1-0}+0\times 3^{2}-\frac{6}{25}\right)\left(-3\right)$$

Tangohia te 0 i te 1, ka 1.

$$\left(\sqrt{1}+0\times 3^{2}-\frac{6}{25}\right)\left(-3\right)$$

Tātaitia te pūtakerua o 1 kia tae ki 1.

$$\left(1+0\times 3^{2}-\frac{6}{25}\right)\left(-3\right)$$

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$\left(1+0\times 9-\frac{6}{25}\right)\left(-3\right)$$

Whakareatia te 0 ki te 9, ka 0.

$$\left(1+0-\frac{6}{25}\right)\left(-3\right)$$

Tāpirihia te 1 ki te 0, ka 1.

$$\left(1-\frac{6}{25}\right)\left(-3\right)$$

Me tahuri te 1 ki te hautau \frac{25}{25}.

$$\left(\frac{25}{25}-\frac{6}{25}\right)\left(-3\right)$$

Tā te mea he rite te tauraro o \frac{25}{25} me \frac{6}{25}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{25-6}{25}\left(-3\right)$$

Tangohia te 6 i te 25, ka 19.

$$\frac{19}{25}\left(-3\right)$$

Tuhia te \frac{19}{25}\left(-3\right) hei hautanga kotahi.

$$\frac{19\left(-3\right)}{25}$$

Whakareatia te 19 ki te -3, ka -57.

$$\frac{-57}{25}$$

Ka taea te hautanga \frac{-57}{25} te tuhi anō ko -\frac{57}{25} mā te tango i te tohu tōraro.

$$-\frac{57}{25}$$

Tauwehe

$$-\frac{57}{25} = -2\frac{7}{25} = -2.28$$