Whakaoti i te (sqrt{(-5)^2}+sqrt[3]{(-3)^3})*sqrt{2^frac{1{3}}*2^-frac{7{3}}}

$$( \sqrt { ( - 5 ) ^ { 2 } } + \sqrt[ 3 ] { ( - 3 ) ^ { 3 } } ) \cdot \sqrt { 2 ^ { \frac { 1 } { 3 } } \cdot 2 ^ { - \frac { 7 } { 3 } } }$$

Aromātai

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Ngā Upane Otinga

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te \frac{1}{3} me te -\frac{7}{3} kia riro ai te -2.

$$\left(\sqrt{\left(-5\right)^{2}}+\sqrt[3]{\left(-3\right)^{3}}\right)\sqrt{2^{-2}}$$

Tātaihia te -5 mā te pū o 2, kia riro ko 25.

$$\left(\sqrt{25}+\sqrt[3]{\left(-3\right)^{3}}\right)\sqrt{2^{-2}}$$

Tātaitia te pūtakerua o 25 kia tae ki 5.

$$\left(5+\sqrt[3]{\left(-3\right)^{3}}\right)\sqrt{2^{-2}}$$

Tātaihia te -3 mā te pū o 3, kia riro ko -27.

$$\left(5+\sqrt[3]{-27}\right)\sqrt{2^{-2}}$$

Tātaitia te \sqrt[3]{-27} kia tae ki -3.

$$\left(5-3\right)\sqrt{2^{-2}}$$

Tangohia te 3 i te 5, ka 2.

$$2\sqrt{2^{-2}}$$

Tātaihia te 2 mā te pū o -2, kia riro ko \frac{1}{4}.

$$2\sqrt{\frac{1}{4}}$$

Tuhia anō te pūtake rua o te whakawehenga \frac{1}{4} hei whakawehenga o ngā pūtake rua \frac{\sqrt{1}}{\sqrt{4}}. Tuhia te pūtakerua o te taurunga me te tauraro.

$$2\times \frac{1}{2}$$

Whakareatia te 2 ki te \frac{1}{2}, ka 1.

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Tauwehe

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