Whakaoti i te (log4+2)^2-(log4+4)*log4=

$$( \log 4 + 2 ) ^ { 2 } - ( \log 4 + 4 ) \cdot \log 4 =$$

Aromātai

$$4$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(a+b\right)^{2}=a^{2}+2ab+b^{2} hei whakaroha \left(\log_{10}\left(4\right)+2\right)^{2}.

$$\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)+4-\left(\log_{10}\left(4\right)+4\right)\log_{10}\left(4\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \log_{10}\left(4\right)+4 ki te \log_{10}\left(4\right).

$$\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)+4-\left(\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)\right)$$

Hei kimi i te tauaro o \left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right), kimihia te tauaro o ia taurangi.

$$\left(\log_{10}\left(4\right)\right)^{2}+4\log_{10}\left(4\right)+4-\left(\log_{10}\left(4\right)\right)^{2}-4\log_{10}\left(4\right)$$

Pahekotia te \left(\log_{10}\left(4\right)\right)^{2} me -\left(\log_{10}\left(4\right)\right)^{2}, ka 0.

$$4\log_{10}\left(4\right)+4-4\log_{10}\left(4\right)$$

Pahekotia te 4\log_{10}\left(4\right) me -4\log_{10}\left(4\right), ka 0.

$$4$$

Tauwehe

$$2^{2}$$