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\frac{1}{2}-\frac{6}{2}>1
Me tahuri te 3 ki te hautau \frac{6}{2}.
\frac{1-6}{2}>1
Tā te mea he rite te tauraro o \frac{1}{2} me \frac{6}{2}, me tango rāua mā te tango i ō raua taurunga.
-\frac{5}{2}>1
Tangohia te 6 i te 1, ka -5.
-\frac{5}{2}>\frac{2}{2}
Me tahuri te 1 ki te hautau \frac{2}{2}.
\text{false}
Whakatauritea te -\frac{5}{2} me te \frac{2}{2}.