Whakaoti i te (x^8y^-4/16y^frac{4{3}})^-1/4

$$( \frac { x ^ { 8 } y ^ { - 4 } } { 16 y ^ { \frac { 4 } { 3 } } } ) ^ { - 1 / 4 }$$

Aromātai

$$\frac{2y^{\frac{4}{3}}}{x^{2}}$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te taurunga i te taupū o te tauraro.

$$\left(\frac{x^{8}}{16y^{\frac{16}{3}}}\right)^{-\frac{1}{4}}$$

Kia whakarewa i te \frac{x^{8}}{16y^{\frac{16}{3}}} ki tētahi taupū, me whakarewa tahi te taurunga me te tauraro ki te taupū kātahi ka whakawehe.

$$\frac{\left(x^{8}\right)^{-\frac{1}{4}}}{\left(16y^{\frac{16}{3}}\right)^{-\frac{1}{4}}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 8 me te -\frac{1}{4} kia riro ai te -2.

$$\frac{x^{-2}}{\left(16y^{\frac{16}{3}}\right)^{-\frac{1}{4}}}$$

Whakarohaina te \left(16y^{\frac{16}{3}}\right)^{-\frac{1}{4}}.

$$\frac{x^{-2}}{16^{-\frac{1}{4}}\left(y^{\frac{16}{3}}\right)^{-\frac{1}{4}}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te \frac{16}{3} me te -\frac{1}{4} kia riro ai te -\frac{4}{3}.

$$\frac{x^{-2}}{16^{-\frac{1}{4}}y^{-\frac{4}{3}}}$$

Tātaihia te 16 mā te pū o -\frac{1}{4}, kia riro ko \frac{1}{2}.

$$\frac{x^{-2}}{\frac{1}{2}y^{-\frac{4}{3}}}$$

Kimi Pārōnaki e ai ki x

$$-\frac{4y^{\frac{4}{3}}}{x^{3}}$$