Whakaoti i te (x^4/4-x^3-14x^2)]_-4^0=

$$( \frac { x ^ { 4 } } { 4 } - x ^ { 3 } - 14 x ^ { 2 } ) ] _ { - 4 } ^ { 0 } =$$

Aromātai

$$\frac{x^{2}\left(x^{2}-4x-56\right)}{4}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Whakareatia -x^{3}-14x^{2} ki te \frac{4}{4}.

$$\frac{x^{4}}{4}+\frac{4\left(-x^{3}-14x^{2}\right)}{4}$$

Tā te mea he rite te tauraro o \frac{x^{4}}{4} me \frac{4\left(-x^{3}-14x^{2}\right)}{4}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{x^{4}+4\left(-x^{3}-14x^{2}\right)}{4}$$

Mahia ngā whakarea i roto o x^{4}+4\left(-x^{3}-14x^{2}\right).

$$\frac{x^{4}-4x^{3}-56x^{2}}{4}$$

Tauwehe

$$\frac{\left(x-\left(2-2\sqrt{15}\right)\right)\left(x-\left(2\sqrt{15}+2\right)\right)x^{2}}{4}$$