Whakaoti i te (t/4)(t)

$$( \frac { t } { 4 } ) ( t )$$

Aromātai

$$\frac{t^{2}}{4}$$

Ngā Upane Otinga

Tuhia te \frac{t}{4}t hei hautanga kotahi.

$$\frac{tt}{4}$$

Whakareatia te t ki te t, ka t^{2}.

$$\frac{t^{2}}{4}$$

Kimi Pārōnaki e ai ki t

$$\frac{t}{2}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Hua

Mo ētahi pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te hua o ngā pānga e rua ko te pānga tuatahi whakareatia ki te pārōnaki o te pānga tuarua tāpiri i te pānga tuarua whakareatia ki te pārōnaki o te mea tuatahi.

$$\frac{1}{4}t^{1}\frac{\mathrm{d}}{\mathrm{d}t}(t^{1})+t^{1}\frac{\mathrm{d}}{\mathrm{d}t}(\frac{1}{4}t^{1})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{1}{4}t^{1}t^{1-1}+t^{1}\times \frac{1}{4}t^{1-1}$$

Whakarūnātia.

$$\frac{1}{4}t^{1}t^{0}+t^{1}\times \frac{1}{4}t^{0}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{1}{4}t^{1}+\frac{1}{4}t^{1}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{1+1}{4}t^{1}$$

Tāpiri \frac{1}{4} ki te \frac{1}{4} mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$\frac{1}{2}t^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{1}{2}t$$