Whakaoti i te (k/3)(k/4)

$$( \frac { k } { 3 } ) ( \frac { k } { 4 } )$$

Aromātai

$$\frac{k^{2}}{12}$$

Ngā Upane Otinga

Me whakarea te \frac{k}{3} ki te \frac{k}{4} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{kk}{3\times 4}$$

Whakareatia te k ki te k, ka k^{2}.

$$\frac{k^{2}}{3\times 4}$$

Whakareatia te 3 ki te 4, ka 12.

$$\frac{k^{2}}{12}$$

Kimi Pārōnaki e ai ki k

$$\frac{k}{6}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Hua

Mo ētahi pānga e rua e taea ana te pārōnaki, ko te pārōnaki o te hua o ngā pānga e rua ko te pānga tuatahi whakareatia ki te pārōnaki o te pānga tuarua tāpiri i te pānga tuarua whakareatia ki te pārōnaki o te mea tuatahi.

$$\frac{1}{3}k^{1}\frac{\mathrm{d}}{\mathrm{d}k}(\frac{1}{4}k^{1})+\frac{1}{4}k^{1}\frac{\mathrm{d}}{\mathrm{d}k}(\frac{1}{3}k^{1})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{1}{3}k^{1}\times \frac{1}{4}k^{1-1}+\frac{1}{4}k^{1}\times \frac{1}{3}k^{1-1}$$

Whakarūnātia.

$$\frac{1}{3}k^{1}\times \frac{1}{4}k^{0}+\frac{1}{4}k^{1}\times \frac{1}{3}k^{0}$$

Hei whakarea pū o te pūtake ōrite, tāpiri ana taupū.

$$\frac{1}{4}\times \frac{1}{3}k^{1}+\frac{1}{4}\times \frac{1}{3}k^{1}$$

Whakarūnātia.

$$\frac{1}{12}k^{1}+\frac{1}{12}k^{1}$$

Pahekotia ngā kīanga tau ōrite.

$$\frac{1+1}{12}k^{1}$$

Tāpiri \frac{1}{12} ki te \frac{1}{12} mā te kimi i te tauraro pātahi me te tāpiri i ngā taurunga. Ka whakaiti i te hautanga ki ngā kīanga tau iti rawa e taea ana.

$$\frac{1}{6}k^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$\frac{1}{6}k$$