Whakaoti i te (frac{6f^{2}g^-8h^2}{32fg^-5h^4})

$$( \frac { 6 f ^ { 2 } g ^ { - 8 } h ^ { 2 } } { 32 f g ^ { - 5 } h ^ { 4 } } )$$

Aromātai

$$\frac{3f}{16h^{2}g^{3}}$$

Ngā Upane Otinga

Me whakakore tahi te 2fh^{2} i te taurunga me te tauraro.

$$\frac{3g^{-8}f}{16g^{-5}h^{2}}$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te taurunga i te taupū o te tauraro.

$$\frac{3f}{16h^{2}g^{3}}$$

Kimi Pārōnaki e ai ki f

$$\frac{3}{16h^{2}g^{3}}$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}f}(\frac{6h^{2}}{g^{8}\times \frac{32h^{4}}{g^{5}}}f^{2-1})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}f}(\frac{3}{16h^{2}g^{3}}f^{1})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{3}{16h^{2}g^{3}}f^{1-1}$$

Mahia ngā tātaitanga.

$$\frac{3}{16h^{2}g^{3}}f^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{3}{16h^{2}g^{3}}\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{3}{16h^{2}g^{3}}$$