Whakaoti i te (4/5x-7/8x):1/x^2

$$( \frac { 4 } { 5 x } - \frac { 7 } { 8 x } ) : \frac { 1 } { x ^ { 2 } }$$

Aromātai

$$-\frac{3x}{40}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 5x me 8x ko 40x. Whakareatia \frac{4}{5x} ki te \frac{8}{8}. Whakareatia \frac{7}{8x} ki te \frac{5}{5}.

$$\frac{\frac{4\times 8}{40x}-\frac{7\times 5}{40x}}{\frac{1}{x^{2}}}$$

Tā te mea he rite te tauraro o \frac{4\times 8}{40x} me \frac{7\times 5}{40x}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\frac{4\times 8-7\times 5}{40x}}{\frac{1}{x^{2}}}$$

Mahia ngā whakarea i roto o 4\times 8-7\times 5.

$$\frac{\frac{32-35}{40x}}{\frac{1}{x^{2}}}$$

Mahia ngā tātaitai i roto o 32-35.

$$\frac{\frac{-3}{40x}}{\frac{1}{x^{2}}}$$

Whakawehe \frac{-3}{40x} ki te \frac{1}{x^{2}} mā te whakarea \frac{-3}{40x} ki te tau huripoki o \frac{1}{x^{2}}.

$$\frac{-3x^{2}}{40x}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$\frac{-3x}{40}$$

Whakaroha

$$-\frac{3x}{40}$$

Ngā Hipanga Rongoā Poto

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o 5x me 8x ko 40x. Whakareatia \frac{4}{5x} ki te \frac{8}{8}. Whakareatia \frac{7}{8x} ki te \frac{5}{5}.

$$\frac{\frac{4\times 8}{40x}-\frac{7\times 5}{40x}}{\frac{1}{x^{2}}}$$

Tā te mea he rite te tauraro o \frac{4\times 8}{40x} me \frac{7\times 5}{40x}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{\frac{4\times 8-7\times 5}{40x}}{\frac{1}{x^{2}}}$$

Mahia ngā whakarea i roto o 4\times 8-7\times 5.

$$\frac{\frac{32-35}{40x}}{\frac{1}{x^{2}}}$$

Mahia ngā tātaitai i roto o 32-35.

$$\frac{\frac{-3}{40x}}{\frac{1}{x^{2}}}$$

Whakawehe \frac{-3}{40x} ki te \frac{1}{x^{2}} mā te whakarea \frac{-3}{40x} ki te tau huripoki o \frac{1}{x^{2}}.

$$\frac{-3x^{2}}{40x}$$

Me whakakore tahi te x i te taurunga me te tauraro.

$$\frac{-3x}{40}$$