Whakaoti i te (3/2div9/2)+(-2/3*1/3)

$$( \frac { 3 } { 2 } \div \frac { 9 } { 2 } ) + ( - \frac { 2 } { 3 } \cdot \frac { 1 } { 3 } )$$

Aromātai

$$\frac{1}{9}\approx 0.111111111$$

Ngā Upane Otinga

Whakawehe \frac{3}{2} ki te \frac{9}{2} mā te whakarea \frac{3}{2} ki te tau huripoki o \frac{9}{2}.

$$\frac{3}{2}\times \frac{2}{9}-\frac{2}{3}\times \frac{1}{3}$$

Me whakarea te \frac{3}{2} ki te \frac{2}{9} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{3\times 2}{2\times 9}-\frac{2}{3}\times \frac{1}{3}$$

Me whakakore tahi te 2 i te taurunga me te tauraro.

$$\frac{3}{9}-\frac{2}{3}\times \frac{1}{3}$$

Whakahekea te hautanga \frac{3}{9} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$\frac{1}{3}-\frac{2}{3}\times \frac{1}{3}$$

Me whakarea te -\frac{2}{3} ki te \frac{1}{3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{1}{3}+\frac{-2}{3\times 3}$$

Mahia ngā whakarea i roto i te hautanga \frac{-2}{3\times 3}.

$$\frac{1}{3}+\frac{-2}{9}$$

Ka taea te hautanga \frac{-2}{9} te tuhi anō ko -\frac{2}{9} mā te tango i te tohu tōraro.

$$\frac{1}{3}-\frac{2}{9}$$

Ko te maha noa iti rawa atu o 3 me 9 ko 9. Me tahuri \frac{1}{3} me \frac{2}{9} ki te hautau me te tautūnga 9.

$$\frac{3}{9}-\frac{2}{9}$$

Tā te mea he rite te tauraro o \frac{3}{9} me \frac{2}{9}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{3-2}{9}$$

Tangohia te 2 i te 3, ka 1.

$$\frac{1}{9}$$

Tauwehe

$$\frac{1}{3 ^ {2}} = 0.1111111111111111$$