Whakaoti i te (2x^4z^-4/8x^3yz^2)

$$( \frac { 2 x ^ { 4 } z ^ { - 4 } } { 8 x ^ { 3 } y z ^ { 2 } } )$$

Aromātai

$$\frac{x}{4yz^{6}}$$

Ngā Upane Otinga

Me whakakore tahi te 2x^{3} i te taurunga me te tauraro.

$$\frac{z^{-4}x}{4yz^{2}}$$

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te taurunga i te taupū o te tauraro.

$$\frac{x}{4yz^{6}}$$

Kimi Pārōnaki e ai ki x

$$\frac{1}{4yz^{6}}$$

Ngā Upane Otinga

Hei whakawehe i ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{2}{z^{4}\times 8yz^{2}}x^{4-3})$$

Mahia ngā tātaitanga.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{1}{4yz^{6}}x^{1})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$\frac{1}{4yz^{6}}x^{1-1}$$

Mahia ngā tātaitanga.

$$\frac{1}{4yz^{6}}x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{1}{4yz^{6}}\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{1}{4yz^{6}}$$