Whakaoti i te (1/z)^2

$$( \frac { 1 } { z } ) ^ { 2 }$$

Aromātai

$$\frac{1}{z^{2}}$$

Ngā Upane mō te Hāpai i Tētahi Pū ki Tētahi Atu Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\left(\frac{1}{z}\right)^{2}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū.

$$z^{-2}$$

Whakareatia -1 ki te 2.

$$\frac{1}{z^{2}}$$

Ngā Upane mō te Hāpai i te Otinga ki tētahi Pū

Whakamahia ngā ture taupū hei whakarūnā i te kīanga.

$$\left(\frac{1}{z^{1}}\right)^{2}$$

Hei hiki i te otinga o ngā tau e rua ki tētahi pū, hīkina ia tau ki te pū ka whakawehe.

$$\frac{1^{2}}{\left(z^{1}\right)^{2}}$$

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū.

$$\frac{1}{z^{2}}$$

Kimi Pārōnaki e ai ki z

$$-\frac{2}{z^{3}}$$

Ngā Upane e Whakamahi ana i te Ture Mekameka

Mēnā ko F te hanganga o ngā pānga e rua e taea ana te pārōnaki f\left(u\right) me u=g\left(x\right), arā, mēnā ko F\left(x\right)=f\left(g\left(x\right)\right), ko te pārōnaki o F te pārōnaki o f e ai ki u whakareatia te pārōnaki o g e ai ki x, arā, \frac{\mathrm{d}}{\mathrm{d}x}(F)\left(x\right)=\frac{\mathrm{d}}{\mathrm{d}x}(f)\left(g\left(x\right)\right)\frac{\mathrm{d}}{\mathrm{d}x}(g)\left(x\right).

$$2\times \left(\frac{1}{z}\right)^{2-1}\frac{\mathrm{d}}{\mathrm{d}z}(\frac{1}{z})$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2\times \left(\frac{1}{z}\right)^{1}\left(-1\right)z^{-1-1}$$

Whakarūnātia.

$$-2z^{-2}\times \left(\frac{1}{z}\right)^{1}$$

Mō tētahi kupu t, t^{1}=t.

$$-2z^{-2}\times \frac{1}{z}$$