Whakaoti i te (1/x+3+6/x^2-9)+1/x^2-6x+914

$$( \frac { 1 } { x + 3 } + \frac { 6 } { x ^ { 2 } - 9 } ) + \frac { 1 } { x ^ { 2 } - 6 x + 9 } 14$$

Aromātai

$$\frac{x+11}{\left(x-3\right)^{2}}$$

Ngā Hipanga Rongoā Poto

Tuhia te \frac{1}{x^{2}-6x+9}\times 14 hei hautanga kotahi.

$$\frac{1}{x+3}+\frac{6}{x^{2}-9}+\frac{14}{x^{2}-6x+9}$$

Tauwehea te x^{2}-9.

$$\frac{1}{x+3}+\frac{6}{\left(x-3\right)\left(x+3\right)}+\frac{14}{x^{2}-6x+9}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x+3 me \left(x-3\right)\left(x+3\right) ko \left(x-3\right)\left(x+3\right). Whakareatia \frac{1}{x+3} ki te \frac{x-3}{x-3}.

$$\frac{x-3}{\left(x-3\right)\left(x+3\right)}+\frac{6}{\left(x-3\right)\left(x+3\right)}+\frac{14}{x^{2}-6x+9}$$

Tā te mea he rite te tauraro o \frac{x-3}{\left(x-3\right)\left(x+3\right)} me \frac{6}{\left(x-3\right)\left(x+3\right)}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{x-3+6}{\left(x-3\right)\left(x+3\right)}+\frac{14}{x^{2}-6x+9}$$

Whakakotahitia ngā kupu rite i x-3+6.

$$\frac{x+3}{\left(x-3\right)\left(x+3\right)}+\frac{14}{x^{2}-6x+9}$$

Me whakakore tahi te x+3 i te taurunga me te tauraro.

$$\frac{1}{x-3}+\frac{14}{x^{2}-6x+9}$$

Tauwehea te x^{2}-6x+9.

$$\frac{1}{x-3}+\frac{14}{\left(x-3\right)^{2}}$$

Hei tāpiri, hei tango kīanga rānei, me whakaroha ērā kia rite ā rātou tauraro. Ko te taurea pātahi iti rawa o x-3 me \left(x-3\right)^{2} ko \left(x-3\right)^{2}. Whakareatia \frac{1}{x-3} ki te \frac{x-3}{x-3}.

$$\frac{x-3}{\left(x-3\right)^{2}}+\frac{14}{\left(x-3\right)^{2}}$$

Tā te mea he rite te tauraro o \frac{x-3}{\left(x-3\right)^{2}} me \frac{14}{\left(x-3\right)^{2}}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{x-3+14}{\left(x-3\right)^{2}}$$

Whakakotahitia ngā kupu rite i x-3+14.

$$\frac{x+11}{\left(x-3\right)^{2}}$$

Whakarohaina te \left(x-3\right)^{2}.

$$\frac{x+11}{x^{2}-6x+9}$$

Kimi Pārōnaki e ai ki x

$$\frac{-x-25}{\left(x-3\right)^{3}}$$