Whakaoti i te (1/8-x^3):(x-1/2)

$$( \frac { 1 } { 8 } - x ^ { 3 } ) : ( x - \frac { 1 } { 2 } )$$

Aromātai

$$-x^{2}-\frac{x}{2}-\frac{1}{4}$$

Ngā Hipanga Rongoā Poto

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{\frac{1}{8}\left(2x-1\right)\left(-4x^{2}-2x-1\right)}{\frac{1}{2}\left(2x-1\right)}$$

Me whakakore tahi te 2x-1 i te taurunga me te tauraro.

$$\frac{\frac{1}{8}\left(-4x^{2}-2x-1\right)}{\frac{1}{2}}$$

Me whakaroha te kīanga.

$$\frac{-\frac{1}{2}x^{2}-\frac{1}{4}x-\frac{1}{8}}{\frac{1}{2}}$$

Whakawehe -\frac{1}{2}x^{2}-\frac{1}{4}x-\frac{1}{8} ki te \frac{1}{2} mā te whakarea -\frac{1}{2}x^{2}-\frac{1}{4}x-\frac{1}{8} ki te tau huripoki o \frac{1}{2}.

$$\left(-\frac{1}{2}x^{2}-\frac{1}{4}x-\frac{1}{8}\right)\times 2$$

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{2}x^{2}-\frac{1}{4}x-\frac{1}{8} ki te 2.

$$-x^{2}-\frac{1}{2}x-\frac{1}{4}$$

Whakaroha

$$-x^{2}-\frac{x}{2}-\frac{1}{4}$$

Ngā Hipanga Rongoā Poto

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{\frac{1}{8}\left(2x-1\right)\left(-4x^{2}-2x-1\right)}{\frac{1}{2}\left(2x-1\right)}$$

Me whakakore tahi te 2x-1 i te taurunga me te tauraro.

$$\frac{\frac{1}{8}\left(-4x^{2}-2x-1\right)}{\frac{1}{2}}$$

Me whakaroha te kīanga.

$$\frac{-\frac{1}{2}x^{2}-\frac{1}{4}x-\frac{1}{8}}{\frac{1}{2}}$$

Whakawehe -\frac{1}{2}x^{2}-\frac{1}{4}x-\frac{1}{8} ki te \frac{1}{2} mā te whakarea -\frac{1}{2}x^{2}-\frac{1}{4}x-\frac{1}{8} ki te tau huripoki o \frac{1}{2}.

$$\left(-\frac{1}{2}x^{2}-\frac{1}{4}x-\frac{1}{8}\right)\times 2$$

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{2}x^{2}-\frac{1}{4}x-\frac{1}{8} ki te 2.

$$-x^{2}-\frac{1}{2}x-\frac{1}{4}$$