Whakaoti i te (1/5(x-10)>1/10-2/15

$$( \frac { 1 } { 5 } ( x - 10 ) > \frac { 1 } { 10 } - \frac { 2 } { 15 }$$

Whakaoti mō x

$$x>\frac{59}{6}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{5} ki te x-10.

$$\frac{1}{5}x+\frac{1}{5}\left(-10\right)>\frac{1}{10}-\frac{2}{15}$$

Whakareatia te \frac{1}{5} ki te -10, ka \frac{-10}{5}.

$$\frac{1}{5}x+\frac{-10}{5}>\frac{1}{10}-\frac{2}{15}$$

Whakawehea te -10 ki te 5, kia riro ko -2.

$$\frac{1}{5}x-2>\frac{1}{10}-\frac{2}{15}$$

Ko te maha noa iti rawa atu o 10 me 15 ko 30. Me tahuri \frac{1}{10} me \frac{2}{15} ki te hautau me te tautūnga 30.

$$\frac{1}{5}x-2>\frac{3}{30}-\frac{4}{30}$$

Tā te mea he rite te tauraro o \frac{3}{30} me \frac{4}{30}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{1}{5}x-2>\frac{3-4}{30}$$

Tangohia te 4 i te 3, ka -1.

$$\frac{1}{5}x-2>-\frac{1}{30}$$

Me tāpiri te 2 ki ngā taha e rua.

$$\frac{1}{5}x>-\frac{1}{30}+2$$

Me tahuri te 2 ki te hautau \frac{60}{30}.

$$\frac{1}{5}x>-\frac{1}{30}+\frac{60}{30}$$

Tā te mea he rite te tauraro o -\frac{1}{30} me \frac{60}{30}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{1}{5}x>\frac{-1+60}{30}$$

Tāpirihia te -1 ki te 60, ka 59.

$$\frac{1}{5}x>\frac{59}{30}$$

Me whakarea ngā taha e rua ki te 5, te tau utu o \frac{1}{5}. I te mea he tōrunga te \frac{1}{5}, kāore e huri te ahunga koreōrite.

$$x>\frac{59}{30}\times 5$$

Tuhia te \frac{59}{30}\times 5 hei hautanga kotahi.

$$x>\frac{59\times 5}{30}$$

Whakareatia te 59 ki te 5, ka 295.

$$x>\frac{295}{30}$$

Whakahekea te hautanga \frac{295}{30} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 5.

$$x>\frac{59}{6}$$