Whakaoti i te (1/25)^0+frac{1/4*16+sqrt[4]{16}}{2^-1}

$$( \frac { 1 } { 25 } ) ^ { 0 } + \frac { \frac { 1 } { 4 } \cdot 16 + \sqrt[ 4 ] { 16 } } { 2 ^ { - 1 } }$$

Aromātai

$$13$$

Ngā Upane Otinga

Tātaihia te \frac{1}{25} mā te pū o 0, kia riro ko 1.

$$1+\frac{\frac{1}{4}\times 16+\sqrt[4]{16}}{2^{-1}}$$

Whakareatia te \frac{1}{4} ki te 16, ka 4.

$$1+\frac{4+\sqrt[4]{16}}{2^{-1}}$$

Tātaitia te \sqrt[4]{16} kia tae ki 2.

$$1+\frac{4+2}{2^{-1}}$$

Tāpirihia te 4 ki te 2, ka 6.

$$1+\frac{6}{2^{-1}}$$

Tātaihia te 2 mā te pū o -1, kia riro ko \frac{1}{2}.

$$1+\frac{6}{\frac{1}{2}}$$

Whakawehe 6 ki te \frac{1}{2} mā te whakarea 6 ki te tau huripoki o \frac{1}{2}.

$$1+6\times 2$$

Whakareatia te 6 ki te 2, ka 12.

$$1+12$$

Tāpirihia te 1 ki te 12, ka 13.

$$13$$

Tauwehe

$$13$$