Whakaoti i te (1/2-a)^2-3(a-1/2)(a+1/2)+2(a-1)^2

$$( \frac { 1 } { 2 } - a ) ^ { 2 } - 3 ( a - \frac { 1 } { 2 } ) ( a + \frac { 1 } { 2 } ) + 2 ( a - 1 ) ^ { 2 }$$

Aromātai

$$3-5a$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(p-q\right)^{2}=p^{2}-2pq+q^{2} hei whakaroha \left(\frac{1}{2}-a\right)^{2}.

$$\frac{1}{4}-a+a^{2}-3\left(a-\frac{1}{2}\right)\left(a+\frac{1}{2}\right)+2\left(a-1\right)^{2}$$

Whakamahia te ture huarua \left(p-q\right)^{2}=p^{2}-2pq+q^{2} hei whakaroha \left(a-1\right)^{2}.

$$\frac{1}{4}-a+a^{2}-3\left(a-\frac{1}{2}\right)\left(a+\frac{1}{2}\right)+2\left(a^{2}-2a+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te a^{2}-2a+1.

$$\frac{1}{4}-a+a^{2}-3\left(a-\frac{1}{2}\right)\left(a+\frac{1}{2}\right)+2a^{2}-4a+2$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te a-\frac{1}{2}.

$$\frac{1}{4}-a+a^{2}+\left(-3a+\frac{3}{2}\right)\left(a+\frac{1}{2}\right)+2a^{2}-4a+2$$

Whakamahia te āhuatanga tuaritanga hei whakarea te -3a+\frac{3}{2} ki te a+\frac{1}{2} ka whakakotahi i ngā kupu rite.

$$\frac{1}{4}-a+a^{2}-3a^{2}+\frac{3}{4}+2a^{2}-4a+2$$

Pahekotia te a^{2} me -3a^{2}, ka -2a^{2}.

$$\frac{1}{4}-a-2a^{2}+\frac{3}{4}+2a^{2}-4a+2$$

Tāpirihia te \frac{1}{4} ki te \frac{3}{4}, ka 1.

$$1-a-2a^{2}+2a^{2}-4a+2$$

Pahekotia te -2a^{2} me 2a^{2}, ka 0.

$$1-a-4a+2$$

Pahekotia te -a me -4a, ka -5a.

$$1-5a+2$$

Tāpirihia te 1 ki te 2, ka 3.

$$3-5a$$

Whakaroha

$$3-5a$$

Ngā Upane Otinga

Whakamahia te ture huarua \left(p-q\right)^{2}=p^{2}-2pq+q^{2} hei whakaroha \left(\frac{1}{2}-a\right)^{2}.

$$\frac{1}{4}-a+a^{2}-3\left(a-\frac{1}{2}\right)\left(a+\frac{1}{2}\right)+2\left(a-1\right)^{2}$$

Whakamahia te ture huarua \left(p-q\right)^{2}=p^{2}-2pq+q^{2} hei whakaroha \left(a-1\right)^{2}.

$$\frac{1}{4}-a+a^{2}-3\left(a-\frac{1}{2}\right)\left(a+\frac{1}{2}\right)+2\left(a^{2}-2a+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te a^{2}-2a+1.

$$\frac{1}{4}-a+a^{2}-3\left(a-\frac{1}{2}\right)\left(a+\frac{1}{2}\right)+2a^{2}-4a+2$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te a-\frac{1}{2}.

$$\frac{1}{4}-a+a^{2}+\left(-3a+\frac{3}{2}\right)\left(a+\frac{1}{2}\right)+2a^{2}-4a+2$$

Whakamahia te āhuatanga tuaritanga hei whakarea te -3a+\frac{3}{2} ki te a+\frac{1}{2} ka whakakotahi i ngā kupu rite.

$$\frac{1}{4}-a+a^{2}-3a^{2}+\frac{3}{4}+2a^{2}-4a+2$$

Pahekotia te a^{2} me -3a^{2}, ka -2a^{2}.

$$\frac{1}{4}-a-2a^{2}+\frac{3}{4}+2a^{2}-4a+2$$

Tāpirihia te \frac{1}{4} ki te \frac{3}{4}, ka 1.

$$1-a-2a^{2}+2a^{2}-4a+2$$

Pahekotia te -2a^{2} me 2a^{2}, ka 0.

$$1-a-4a+2$$

Pahekotia te -a me -4a, ka -5a.

$$1-5a+2$$

Tāpirihia te 1 ki te 2, ka 3.

$$3-5a$$