Whakaoti i te (-5x-25/5x-x^2*x^2-5x/5x-10)

$$( \frac { - 5 x - 25 } { 5 x - x ^ { 2 } } \cdot \frac { x ^ { 2 } - 5 x } { 5 x - 10 } )$$

Aromātai

$$\frac{x+5}{x-2}$$

Ngā Hipanga Rongoā Poto

Me whakarea te \frac{-5x-25}{5x-x^{2}} ki te \frac{x^{2}-5x}{5x-10} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(-5x-25\right)\left(x^{2}-5x\right)}{\left(5x-x^{2}\right)\left(5x-10\right)}$$

Unuhia te tohu tōraro i roto o x^{2}-5x.

$$\frac{-\left(-5x-25\right)\left(-x^{2}+5x\right)}{\left(5x-10\right)\left(-x^{2}+5x\right)}$$

Me whakakore tahi te -x^{2}+5x i te taurunga me te tauraro.

$$\frac{-\left(-5x-25\right)}{5x-10}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{-5\left(-x-5\right)}{5\left(x-2\right)}$$

Me whakakore tahi te 5 i te taurunga me te tauraro.

$$\frac{-\left(-x-5\right)}{x-2}$$

Me whakaroha te kīanga.

$$\frac{x+5}{x-2}$$

Whakaroha

$$\frac{x+5}{x-2}$$

Ngā Hipanga Rongoā Poto

Me whakarea te \frac{-5x-25}{5x-x^{2}} ki te \frac{x^{2}-5x}{5x-10} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\frac{\left(-5x-25\right)\left(x^{2}-5x\right)}{\left(5x-x^{2}\right)\left(5x-10\right)}$$

Unuhia te tohu tōraro i roto o x^{2}-5x.

$$\frac{-\left(-5x-25\right)\left(-x^{2}+5x\right)}{\left(5x-10\right)\left(-x^{2}+5x\right)}$$

Me whakakore tahi te -x^{2}+5x i te taurunga me te tauraro.

$$\frac{-\left(-5x-25\right)}{5x-10}$$

Me whakatauwehe ngā kīanga kāore anō i whakatauwehea.

$$\frac{-5\left(-x-5\right)}{5\left(x-2\right)}$$

Me whakakore tahi te 5 i te taurunga me te tauraro.

$$\frac{-\left(-x-5\right)}{x-2}$$

Me whakaroha te kīanga.

$$\frac{x+5}{x-2}$$