Whakaoti i te ((x-2)x/8)>0

$$( \frac { ( x - 2 ) x } { 8 } ) > 0$$

Whakaoti mō x

$$x\in \left(-\infty,0\right)\cup \left(2,\infty\right)$$

Ngā Upane Otinga

Me whakarea ngā taha e rua ki te 8. I te mea he tōrunga te 8, kāore e huri te ahunga koreōrite. Ko te tau i whakarea ki te kore ka hua ko te kore.

$$\left(x-2\right)x>0$$

Whakamahia te āhuatanga tohatoha hei whakarea te x-2 ki te x.

$$x^{2}-2x>0$$

Tauwehea te x.

$$x\left(x-2\right)>0$$

Kia tōrunga te otinga, me tōraro tahi te x me te x-2, me tōrunga tahi rānei. Whakaarohia te tauira ina he tōraro tahi te x me te x-2.

$$x<0 x-2<0$$

Te otinga e whakaea i ngā koreōrite e rua ko x<0.

$$x<0$$

Whakaarohia te tauira ina he tōrunga tahi te x me te x-2.

$$x-2>0 x>0$$

Te otinga e whakaea i ngā koreōrite e rua ko x>2.

$$x>2$$

Ko te otinga whakamutunga ko te whakakotahi i ngā otinga kua whiwhi.

$$x<0\text{; }x>2$$